resoudre les equation suivantes

a) [tex]2(x+3) = 3(x+2)[/tex]
[tex]2x +6 = 3x + 6[/tex]
[tex]2x - 3x + 6 - 6 = 0[/tex]
[tex]-x = 0[/tex] donc x=0

c) [tex]3 + 2(x-1) = 3x + 6[/tex]
[tex]3 + 2x -2 = 3x +6[/tex]
[tex]2x + 1 = 3x +6[/tex]
[tex]2x -3x +1-6=0[/tex]
[tex]-x -5 = 0[/tex]
[tex]-x = 5[/tex] donc x = -5

d) [tex]5x - 2(3x+1) = 3(x-7)[/tex]
[tex]5x -6x -2 = 3x -21[/tex]
[tex]-x-2 -3x +21 =0[/tex]
[tex]-4x +19=0[/tex]
[tex]-4x=-19[/tex]
[tex]x = \frac{-19}{-4} =4.75[/tex]

Salut :)

a) 2(x + 3) = 3(x + 2)
2x + 6 = 3x + 6
6 = x + 6
x = 6 - 6
x = 0

b) 3 + 2(x - 1) = 3x + 6
3 + 2x - 2 = 3x + 6
2x + 1 = 3x + 6
1 = x + 6
x = - 5

c) 5x - 2(3x + 1) = 3(x - 7)
5x - 6x - 2 = 3x - 21
-x - 2 = 3x - 21
-2 = 4x - 21
19 = 4x
x = 19/4

J'espère t'avoir aidé(e) ! :)