F= (3-2a) (a+1) E= (4a+3) (3a+2) D= (y-5) (y-2)
Mathématiques
leilarothoux5
Question
F= (3-2a) (a+1)
E= (4a+3) (3a+2)
D= (y-5) (y-2)
E= (4a+3) (3a+2)
D= (y-5) (y-2)
1 Réponse
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1. Réponse benabidhiba44
Réponse:
F= (3-2a) (a+1)
F=3a+3-2a²-2a
F=a+3-2a²
F=a+3-2a²,a∈ R