Mathématiques

Question

SVP URGENT MERCI A LA PERSONNE QUI POURRA M'AIDER
SVP URGENT MERCI A LA PERSONNE QUI POURRA M'AIDER

1 Réponse

  • A = -2 + x(-5x + 7)
    A = -2 - 5x² + 7x
    A = -5x² + 7x - 2

    B = (x-1)(-5x + 2)
    B = -5x² + 2x + 5x - 2
    B = -5x² + 7x - 2

    C = x(-5x + 5) + 2(x-1)
    C = -5x² + 5x + 2x - 2
    C = -5x² + 7x - 2

    D = -5x(x-2) - (3x + 2)
    D = -5x² + 10x - 3x - 2 
    D = -5x² + 7x - 2 



    [tex]A = \frac{3}{8} - \frac{5}{2} + \frac{1}{6}

     
    A = \frac{18}{48} - \frac{120}{48} + \frac{8}{48}

     
    A = \frac{-94}{48} = \frac{-47}{24} [/tex]



    [tex]B = \frac{5}{3} + 1 - \frac{1}{2}

    B = \frac{10}{} + \frac{6}{6} - \frac{3}{6}

    B = \frac{13}{6} [/tex]


    [tex]C = \frac{6}{7} + ( \frac{3}{7})( \frac{1}{2})

    C = \frac{6}{7} + \frac{3}{14}

    C = \frac{12}{14} + \frac{3}{14}

    C = \frac{15}{14} [/tex]



    [tex]D = \frac{4}{3} + \frac{1}{5} + \frac{4}{5}


    D = \frac{4}{3} + 1

    D = \frac{4}{3} + \frac{3}{3}

    D = \frac{7}{3} [/tex]