SVP URGENT MERCI A LA PERSONNE QUI POURRA M'AIDER
Mathématiques
prissou73
Question
SVP URGENT MERCI A LA PERSONNE QUI POURRA M'AIDER
1 Réponse
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1. Réponse MichaelS
A = -2 + x(-5x + 7)
A = -2 - 5x² + 7x
A = -5x² + 7x - 2
B = (x-1)(-5x + 2)
B = -5x² + 2x + 5x - 2
B = -5x² + 7x - 2
C = x(-5x + 5) + 2(x-1)
C = -5x² + 5x + 2x - 2
C = -5x² + 7x - 2
D = -5x(x-2) - (3x + 2)
D = -5x² + 10x - 3x - 2
D = -5x² + 7x - 2
[tex]A = \frac{3}{8} - \frac{5}{2} + \frac{1}{6}
A = \frac{18}{48} - \frac{120}{48} + \frac{8}{48}
A = \frac{-94}{48} = \frac{-47}{24} [/tex]
[tex]B = \frac{5}{3} + 1 - \frac{1}{2}
B = \frac{10}{} + \frac{6}{6} - \frac{3}{6}
B = \frac{13}{6} [/tex]
[tex]C = \frac{6}{7} + ( \frac{3}{7})( \frac{1}{2})
C = \frac{6}{7} + \frac{3}{14}
C = \frac{12}{14} + \frac{3}{14}
C = \frac{15}{14} [/tex]
[tex]D = \frac{4}{3} + \frac{1}{5} + \frac{4}{5}
D = \frac{4}{3} + 1
D = \frac{4}{3} + \frac{3}{3}
D = \frac{7}{3} [/tex]