Mathématiques

Question

Coucou vous pouvez m'aider s'il vous plait?
Je dois factoriser:
E(x)=81x²-18-3
F(x)=x(x-2)²-4x(x+1)²
G(x)=x(x-1)²-9x(3x+2)²
H(x)=(x+3)³-4x-12
Merci

1 Réponse

  • Réponse :

    Explications étape par étape

    Bonjour

    factoriser:

    E(x)=81x²-18-3

    E = 81x^2 - 21

    E = 3(27x^2 - 7)

    F(x)=x(x-2)²-4x(x+1)²

    F = x[(x - 2)^2 - 2^2(x + 1)^2]

    F = x(x - 2 - 2(x + 1))(x - 2 + 2(x + 1))

    F = x(x - 2 - 2x - 2)(x - 2 + 2x + 2)

    F = x(-x - 4)(3x)

    F = 3x^2(-x - 4)

    G(x)=x(x-1)²-9x(3x+2)²

    G = x[(x - 1)^2 - 3^2(3x + 2)^2]

    G = x(x - 1 - 3(3x + 2))(x - 1 + 3(3x + 2))

    G = x(x - 1 - 9x - 6)(x - 1 + 9x + 6)

    G = x(-8x - 7)(10x + 5)

    G = x(-8x - 7) * 5(2x + 1)

    G = 5x(-8x - 7)(2x + 1)

    H(x)=(x+3)³-4x-12

    H(x) = (x + 3)^3 - 4(x + 3)

    H(x) = (x + 3)[(x + 3)^2 - 4]

    H(x) = (x + 3)(x + 3 - 2)(x + 3 + 2)

    H = (x + 3)(x + 1)(x + 5)

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